0=16x^2+16x-896

Solution for 0=16x^2+16x-896 equation:

0=16x^2+16x-896

We move all terms to the left:

0-(16x^2+16x-896)=0

We add all the numbers together, and all the variables

-(16x^2+16x-896)=0

We get rid of parentheses

-16x^2-16x+896=0

a = -16; b = -16; c = +896;
Δ = b2-4ac
Δ = -162-4·(-16)·896
Δ = 57600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{57600}=240$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-240}{2*-16}=\frac{-224}{-32}
=+7
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+240}{2*-16}=\frac{256}{-32}
=-8
$